Use place value, products, and equal groups to solve larger multiplication and division.
Worked examples
90 ÷ 9 = 10
Put 90 supplies into groups of 9. We want to know how many groups we can make, so this is a division problem.
Think of a multiplication fact: 9 × 9 = 81 is not enough yet, but 9 × 10 = 90 matches the total exactly.
So there are 10 groups of 9, and nothing is left over. The quotient is 10 and the remainder is 0.
Check by multiplying back: 9 × 10 = 90. This is the number of supplies we started with.
58 ÷ 9 = 6 remainder 4
Put 58 shells into groups of 9. Make as many full groups as you can, then see what is left.
Find the closest multiplication fact that does not go over 58: 9 × 6 = 54. So we can make 6 full groups.
Subtract to find the remainder: 58 − 54 = 4. The remainder 4 is smaller than the divisor 9, so no more full group fits.
Check with the divisor, quotient and remainder: 9 × 6 + 4 = 58. This is the number we started with.
100 ÷ 7 = 14 remainder 2
Share 100 cards equally among 7 friends. Each friend gets the same number, and the cards that cannot be shared evenly are left over.
Find the closest multiplication fact that does not go over 100: 7 × 14 = 98. So each friend gets 14 cards.
Subtract to find what is left: 100 − 98 = 2. The remainder 2 is smaller than the divisor 7.
Check by putting the parts back together: 7 × 14 + 2 = 100. This is the total number of cards.
Common mistake
Do not leave a remainder that is as large as the divisor or larger. If it is, another full group still fits, so the quotient is too small. When you check, multiply the divisor by the quotient first and then add the remainder.
Teach-back question
Why must the remainder always be smaller than the divisor? How can you check a division with a remainder by multiplying and adding?
How to play
Read the short story, explore the visual model, and complete five untimed questions. Use the hint when you need a new way to think.
Classroom idea
Ask the learner to explain the model or strategy before choosing an answer, then celebrate a clear explanation as well as a correct result.
Frequently asked questions
What grade is “Share and find remainders” for?
“Share and find remainders” is a Grade 3 Math lesson in NumIO. It practises: division and quotient, division with a remainder.
How does the “Share and find remainders” mission work?
Each mission has five untimed questions. If an answer is not right yet you can try again, and the hint button offers another way to think.
Is “Share and find remainders” free, and do I need an account?
Yes, it is free and there is no account or sign-up. Progress is saved in this browser, so you can come back and continue the mission later.